Question

A car’s engine provides a forward force of 500 N. It is opposed by a resistive force of 200 N. The car accelerates forwards for 20 m. How much work is done by each force? By how much does the car’s energy increase?

Answer 1

$$W_1=500·20=10000\text{ J}.\\ W_2=200·20=4000\text{ J}.\\ \Delta E=W_1-W_2=6000\text{ J}.$$