Question #293726

A ball is thrown at an angle of 50 degrees above the horizontal. After 5 s, the ball is at a distance 38 m along the horizontal from the point where it was released. What is the initial velocity of the ball?


1
Expert's answer
2022-02-04T07:41:38-0500

Velocity:


v=R/(tcosθ)=11.8 m.v=R/(t\cos\theta)=11.8\text{ m}.


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