Question #293642

A vacuum cleaner was pulled with a force of 62.0N at an angle of 60.0° with the horizontal.calculate the work done by the force on the vacuum cleaner as the vacuum is displaced 480cm to the right


1
Expert's answer
2022-02-04T07:42:17-0500

The work is


W=Fdcos⁡θ=62⋅4.8⋅cos⁡60°=149 J.W=Fd\cos\theta=62·4.8·\cos60°=149\text{ J}.


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