Answer to Question #293642 in Physics for Exes

Question #293642

A vacuum cleaner was pulled with a force of 62.0N at an angle of 60.0° with the horizontal.calculate the work done by the force on the vacuum cleaner as the vacuum is displaced 480cm to the right

Expert's answer

The work is

"W=Fd\\cos\\theta=62\u00b74.8\u00b7\\cos60\u00b0=149\\text{ J}."

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