Question #292547

a. the temperature of 200g of water increases from 20 0C to 50 0C in 10 minutes. Calculate:

i. the amount of heat gained by the water

ii. the average rate at which the water is gaining heat


(specific heat capacity of water = 4200 J kg-1 0C-1)


b. Determine the amount of heat that must be removed from 1 kg of water at 40 0C to convert it to ice at -5 0C.

(Obtain any relevant data that you need from the internet. Cite the source of that data in your answer)


Expert's answer

a)

(i) the amount of heat gained by the water

Q=cmΔt=42000.2(5020)=25200JQ=cm\Delta t=4200*0.2*(50-20)=25200\:\rm J

(ii) the average rate at which the water is gaining heat

P=Qτ=252001060=42WP=\frac{Q}{\tau}=\frac{25200}{10*60}=42\:\rm W

b)

Q=cwmΔt1+λm+cicemΔt2=4200140+3300001+210015=508500JQ=c_wm\Delta t_1+\lambda m+c_{ice}m\Delta t_2\\ =4200*1*40+330000*1+2100*1*5\\ =508500\:\rm J


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