Question #292372

A hockey puck B rests in a smooth ice surface and is struck by a second puck A,



which was originally traveling at 40.0 m/s and is deflected 30.0° from its original



direction. The pucks have the same mass. (a) Compute the speed of each puck after



the collision. (b) What fraction of the original kinetic energy of puck A dissipates



during collision?

1
Expert's answer
2022-01-31T11:25:10-0500

Conservation of momentum by axes:


0=muAsinθA+muBsinθB,mvA=muAcosθA+muBcosθB. 0=uAsinθA+uBsinθB,vA=uAcosθA+uBcosθB. uA=29.3 m/s,uB=20.1 m/s.0=mu_A\sin\theta_A+mu_B\sin\theta_B,\\ mv_A=mu_A\cos\theta_A+mu_B\cos\theta_B.\\\space\\ 0=u_A\sin\theta_A+u_B\sin\theta_B,\\ v_A=u_A\cos\theta_A+u_B\cos\theta_B.\\\space\\ u_A =29.3 \text{ m/s},\\ u_B =20.1 \text{ m/s}.

The fraction of energy:


ϵE=vA2uA2vA2=0.46.ϵ_E =\dfrac{v_A^2 −u_A^2}{v_A^2} =0.46.


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