Question #290781

A 4.25 kg block rest on a horizontal tabletop. A cord is attached to this block, the cord passing


over a pulley at the edge of the table. At the end of the cord is hung another block weighing 7


kg. Determine the tension in the cord.

1
Expert's answer
2022-01-27T09:12:25-0500

For the lighter block m and heavier one M write equations for forces acting on them by Newton's second law:


m:T=ma,M:Ma=Mg+T, a=MM+mg=6.1 m/s2, T=25.9 N.m:T=ma,\\M: -Ma=-Mg+T,\\\space\\ a=\dfrac{M}{M+m}g=6.1\text{ m/s}^2,\\\space\\ T=25.9\text{ N}.


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