Question #290778

Determine the resultant of the following: 9.0 N at 40°, 8.0 N at 120°, and 14.0 N at 22 0°, all



angles being measured with the positive x-axis. Use component method in finding the resultant.

1
Expert's answer
2022-01-26T10:27:57-0500
Fx=9cos40°+8cos120°+14cos220°==7.83 N. Fy=9sin40°+8sin120°+14sin220°==3.71 N. FR=Fx2+Fy2=8.6 N, θ=180°arctanFyFx=155°F_x=9\cos40°+8\cos120°+14\cos220°=\\=-7.83\text{ N}.\\\space\\ F_y=9\sin40°+8\sin120°+14\sin 220°=\\=3.71\text{ N}.\\\space\\ F_R=\sqrt{F_x^2+F_y^2} =8.6\text{ N},\\\space\\ \theta=180°-\arctan\dfrac{F_y}{F_x} =155°


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