Question #289936

  1. A can is dropped from rest at a height of 40.0 m above ground. How much time does it spend in the bottom half of its fall?

Expert's answer

Given:

h=40mh=\rm 40\:\rm m

g=9.8m/s2g=9.8\:\rm m/s^2


The time of free falling

t=2hg=2409.8=2.9st=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2*40}{9.8}}=2.9\:\rm s


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