Question #289284

Two like and equal charges are at a distance of d= 5cm and exert a force of F= 9 x 10 -3 N on each other.

a. Find the magnitude of each charge.

b. What is the direction of the electrostatic force between them?



Expert's answer

a) The magnitude of each charge can be found from Coulomb's law:


F=kq2r2q=Fr2k=9×1030.059×1090.2×106CF = k\dfrac{q^2}{r^2}\\ q = \sqrt{\dfrac{Fr^2}{k}} = \sqrt{\dfrac{9\times 10^{-3}\cdot 0.05}{9\times10^9}} \approx 0.2\times 10^{-6}C

b) The force is repulsive, since the particles have the charge of the same kind.


Answer. 0.2×106C0.2\times 10^{-6}C, repulsive.


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