Question

A man pushed a 1,000 kg car to the +x direction. If the applied force is 5000N, what is the acceleration of the the coefficient of the friction force is 0.57

Answer 1

Apply Newton's second law:

$$ma=F_\text{net},\\ ma=F-f,\\ ma=F-\mu mg,\\\space\\ a=\dfrac{F}{m}-\mu g=-0.586\text{ m/s}^2.$$