Question

a hydrogen molecule of mass 3.3×10 raise to power of -27kg is moving with velocity 1.7×10×10×10m/s.calculate it's kinetic energy

Answer 1

$$KE=\dfrac12 mv^2=\dfrac12(3.3·10^{-27})(1.7·10^3),\\\space\\ KE=4.77·10^{-21}\text{ kg},$$

which is equivalent to 0.03 eV.