Question

A 0,25kg volleyball is thrown horizontally at 2 m,s-1 west. It strikes a 0,62kg stationery basketball. The volleyball rebounds eat at 0,79. Calculate the velocity of the basketball immediately after the collision?

Answer 1

By conservation of momentum:

$0.25•2=0.25(-0.79)+0.62•u,\\ u=1.125\text{ m/s}.$