Question #287960

a) The temperature of 200 g of water increases from 20°C to 50°C in 10 minutes. Calculate:

   

i. the amount of heat gained by the water.  

   

ii. the average rate at which the water is gaining heat.    

 

  (Specific heat capacity of water = 4200 J kg-1 OC-1)


 

b) Determine the amount of heat that must be removed from 1 kg of water at 40°C to convert it to ice at -5°C.

 


1
Expert's answer
2022-01-16T13:12:39-0500

(a) Given:

m=0.2kgm=\rm 0.2\: kg

c=4200J/(kg C)c=4200\:\rm J/(kg\ ^\circ C)

t_i=\rm 20\: ^\circ C

t_f=\rm 50\: ^\circ C

τ=10min=600s\tau=\rm 10\: min=600\: s


(i)

Q=cm(tfti)Q=cm(t_f-t_i)

Q=42000.2(5020)=25200JQ=4200*0.2*(50-20)=25200\:\rm J

(ii)

P=Qτ=25200600=42WP=\frac{Q}{\tau}=\frac{25200}{600}=42\:\rm W


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