Question #287669

Two charges q = 6 µC and q2 = +10 µC are placed 12 cm apart. Another charge, q=2 μC is placed in the middle. Determine the magnitude and direction of the force acting on qs by the charge qi and 92.

Expert's answer

F=qiπϵ0r122(q1+q2)=80 N.F=\dfrac {q_i}{\pi\epsilon_0r_{12}^2}\bigg({q_1}+q_2\bigg)=80\text{ N}.


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