Question #287382

A box of mass 5.5kg is resting on a surface and is attached to a hanging 1.0kg bucket by 

lightweight string and a frictionless pulley. The coefficient of static friction between the surface and the box is us=0.40.


a) How many grapes (mgrape =16g) can a student put in the basket without moving the box? T/3


b) When just enough whole grapes have been added to the basket, the system begins to move. If the coefficient of kinetic friction is pk=0.34 between the box and the surface, calculate the

acceleration of the bucket and the tension between the box and bucket. T/4



1
Expert's answer
2022-01-14T09:47:03-0500

a) Find the tension required to move the box. The tension is equal for both box and bucket:


T=μsMg=(m+Nmg)g, N=μsMmmg=75.T=\mu_s Mg=(m+Nm_g)g,\\\space\\ N=\dfrac {\mu_sM-m}{m_g}=75.


b) Calculate the acceleration of the bucket and the tension between the box and bucket. Write the forces acting on the box and bucket with grapes by Newton's second law:

Ma=TμkMg,(m+Nmg)a=(m+Nmg)g+T, a=8.99 m/s2,T=61.6 N.Ma=T-\mu_kMg,\\ -(m+Nm_g)a=-(m+Nm_g)g+T,\\\space\\ a=8.99\text{ m/s}^2,\\ T=61.6\text{ N}.


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