Question #287069
  1. NASA launches the Perseverance on its journey to Mars.  If the rocket is moving with a constant acceleration of 105 m/s2, how long will it take to travel 7400 m?

Formula:  x = x0 + v0t + ½ at2 




  1. A person riding Nitro at Six Flags experiences an acceleration of 5.6 m/s2. As a result, it accelerates from rest to 37.4 m/s. How much distance did the person travel during that acceleration?

Formula: v2 = 2ax






  1. An object accelerates from rest to a speed of 27 m/s over a distance of 62 m. What acceleration did it experience?

Formula: v2 = 2ax





  1. An object accelerates from rest with a constant acceleration of 9.5 m/s2. How fast will it be traveling after it goes 25 m?

Formula: v2 = 2ax




1
Expert's answer
2022-01-14T09:48:40-0500

1. From the formula, find the time (the acceleration is 105 m/s2, the distance is 7400 m):


t=2xa=11.9 s.t=\sqrt\dfrac{2x}{a}=11.9\text{ s}.


2. The distance of the person:


x=v22a=125 m.x=\dfrac {v^2}{2a}=125\text{ m}.


3. The acceleration:


a=v22x=5.88 m/s2.a=\dfrac{v^2}{2x}=5.88\text{ m/s}^2.


4. The speed:


v=2ax=21.8 m/s.v=\sqrt{2ax}=21.8\text{ m/s}.


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