Question #287034

A skier starting from rest accelerates uniformly downhill at 1.8 m/s2 [fwd]. 

How long will it take the skier to reach a point 95 m [fwd] from the starting position?




1
Expert's answer
2022-01-13T09:21:58-0500

The time tt can be found from the kinematic formula:


d=at22d = \dfrac{at^2}{2}

where d=95md = 95m and a=1.8m/s2a = 1.8m/s^2. Thus, obtain:


t=2da=295m1.8m/s210st = \sqrt{\dfrac{2d}{a}} = \sqrt{\dfrac{2\cdot 95m}{1.8m/s^2}} \approx 10s

Answer. 10s.


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