a 400-g ball is released from rest at a hieght of 10m. ignoring air resistance, determine the GPE, KE, and total mechanical energy at each of the following heights: 10m, 7.5m, 5m and 2.5m
GPE: Ep(h)=mgh.KE: Ek(h)=mg(hmax−h).Total: Et(h)=const=mghmax. 10 m:Ep=39.2 J.Ek=0,Et=39.2 J. 7.5 m:Ep=29.4 J.Ek=9.8 J,Et=39.2 J. 5 m:Ep=19.6 J.Ek=19.6 J,Et=39.2 J. 2.5 m:Ep=9.8 J.Ek=29.4 J,Et=39.2 J. \text{GPE: }E_p(h)=mgh.\\ \text{KE: }E_k(h)=mg(h_\text{max}-h).\\ \text{Total: }E_t(h)=\text{const}=mgh_\text{max}.\\\space\\ 10\text{ m}:\\ E_p=39.2\text{ J}.\\ E_k=0,\\ E_t=39.2\text{ J}.\\\space\\ 7.5\text{ m}:\\ E_p=29.4\text{ J}.\\ E_k=9.8\text{ J},\\ E_t=39.2\text{ J}.\\\space\\ 5\text{ m}:\\ E_p=19.6\text{ J}.\\ E_k=19.6\text{ J},\\ E_t=39.2\text{ J}.\\\space\\ 2.5\text{ m}:\\ E_p=9.8\text{ J}.\\ E_k=29.4\text{ J},\\ E_t=39.2\text{ J}.\\\space\\GPE: Ep(h)=mgh.KE: Ek(h)=mg(hmax−h).Total: Et(h)=const=mghmax. 10 m:Ep=39.2 J.Ek=0,Et=39.2 J. 7.5 m:Ep=29.4 J.Ek=9.8 J,Et=39.2 J. 5 m:Ep=19.6 J.Ek=19.6 J,Et=39.2 J. 2.5 m:Ep=9.8 J.Ek=29.4 J,Et=39.2 J.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments