Question

A particle of charge 4.25x10-9 C moves at 3.0x10* m/s at 60° up the x-y plane through a uniform magnetic field of 5.0x10-³T directed along the +z-axis. Find the magnetic force on the particle.

Answer 1

Assuming the speed is 3.0·10² m/s, we have:

$$F=qvB\sin\theta=5.52·10^{-9}\text{ N}.$$