Question

A 124.6-kg object is dropped from a height of 3.8m above a spring with a constant of 14235.8N/m. How much (in cm) will the spring be compressed?

Answer 1

By conservation of energy:

$$\dfrac12kx^2=mgh,\\\space\\ x=\sqrt{\dfrac{2mgh}{k}}=0.8074\text{ m}$$