Question #286453

How much work must be done to accelerate an 800kg car from 15m/s to 30m/s?


Expert's answer

The energy-work theorem gives

ΔE=Wmv222mv122=W\Delta E=W\\ \frac{mv_2^2}{2}-\frac{mv_1^2}{2}=WW=800kg(30m/s)22800kg(15m/s)22W=\rm\frac{800\:kg*(30\:m/s)^2}{2}-\rm\frac{800\:kg*(15\:m/s)^2}{2}

W=270000  JW=\rm 270\: 000\; J


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