Answer to Question #286357 in Physics for Tamatha

Question

1.)How much energy is lost by 20 kg copper if it is cooled from 50℃ to 30℃?

2.)A 20 kg metal rod is heated 100oC with 2000 J of energy. What is the specific heat of the metal?

Answer 1

1)

$$Q=mc\Delta T,$$ $$Q=20\ kg\times385\ \dfrac{J}{kg\times\!^{\circ}C}\times(50^{\circ}C-30^{\circ}C),$$ $$Q=154000\ J=154\ kJ.$$

2)

$$Q=mc\Delta T,$$ $$c=\dfrac{Q}{m\Delta T},$$ $$c=\dfrac{2000\ J}{20\ kg\times100^{\circ}C}=1.0\ \dfrac{J}{kg\times\!^{\circ}C}.$$