Question #286006

A 2kg block at rest is acted upon by a constant force of 20N for 4 seconds. Find: (a). what momentum is required by the block ? (b). Find the final velocity of the block. Show complete solutions.


1
Expert's answer
2022-01-12T08:31:28-0500

a) The required momentum can be found from the second Newton's law:


p=FΔtp = F\Delta t

where F=20N,Δt=4sF = 20N, \Delta t=4s. Thus, obtain:


p=20N4s=80kgm/sp = 20N\cdot 4s = 80 kg\cdot m/s

b) The velocity can be found from the definition of the momentum:


v=pmv = \dfrac{p}{m}

where m=2kgm = 2kg. Thus, obtain:


v=80kgm/s2kg=40m/sv = \dfrac{80kg\cdot m/s}{2kg} = 40m/s

Answer. a) 80kg*m/s, b) 40 m/s.


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