Answer to Question #286005 in Physics for Karen

Question #286005

A 2kg mass is acted upon a force of 50N for 10 seconds. Find: (a). The impulse (b). The change in velocity of the object. Show complete solution.

Expert's answer

(a) "I=Ft=50\u00b710=500\\text{ kg m\/s}."

(b) "\\Delta v=I\/m=500\/2=250\\text{ m\/s}."

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