A 2kg mass is acted upon a force of 50N for 10 seconds. Find: (a). The impulse (b). The change in velocity of the object. Show complete solution.
(a) I=Ft=50⋅10=500 kg m/s.I=Ft=50·10=500\text{ kg m/s}.I=Ft=50⋅10=500 kg m/s.
(b) Δv=I/m=500/2=250 m/s.\Delta v=I/m=500/2=250\text{ m/s}.Δv=I/m=500/2=250 m/s.
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