A roller coaster ride in a park includes a vertical drop of 60m. Assume that the roller coaster has a speed of nearly zero when it reaches the top of the hill. Neglected friction, find the speed of the riders at the bottom of the hill. Show complete solution.
The law of conservation of energy says
"E_i=E_f"Total mechanical energy is a sum of kinetic and potential energy. So
"E_f=0+mgh"
Therefore
"\\frac{mv^2}{2}=mgh"Finally
"v=\\sqrt{2gh}=\\sqrt{2*9.8*60}=34.5\\:\\rm m\/s"
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