Answer to Question #285669 in Physics for awwweee

Question

A 70N force is applied horizontally to a 10kg block at rest for a displacement of 200m across a frictionless surface. How much work is done by the force? What is the acceleration of the block?

Answer 1

Given:

$F=70\:\rm N$

$m=10\:\rm kg$

$d=200\:\rm m$

(a) The work done by the force

$W=Fd=70*200=14000\:\rm J$

(b) The acceleration of a body

$a=\frac{F}{m}=\frac{70}{10}=7\:\rm m/s^2$