Question #285205

A typical pool is 3.0 m deep. What is the water pressure at the bottom of the pool?

Expert's answer

P=ρgh=1000 kgm3×9.8 ms2×3 m=29400 Pa.P=\rho gh=1000\ \dfrac{kg}{m^3}\times 9.8\ \dfrac{m}{s^2}\times 3\ m=29400\ Pa.

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