Question #284773

A force ๐นโƒ— = (6๐šคฬ‚ - ๐šฅฬ‚) N acts on a particle that undergoes a displacement ๐‘‘โƒ— = (3๐šคฬ‚ + ๐šฅฬ‚) m. Find (a) the dot product ๐นโƒ— โ€ข ๐‘‘โƒ— and (b) the angle between ๐นโƒ— and ๐‘‘โƒ—. 


1
Expert's answer
2022-01-04T13:54:38-0500

(a) The dot product:


Fโƒ—โ‹…dโƒ—=(6โ‹…3)+((โˆ’1)โ‹…1)=17 J.\vec Fยท\vec d=(6ยท3)+((-1)ยท1)=17\text{ J}.


(b) The angle:


ฮธ=arccosโกFโƒ—โ‹…dโƒ—โˆฃFโƒ—โˆฃโ‹…โˆฃdโƒ—โˆฃ=28ยฐ.\theta=\arccos\dfrac{\vec Fยท\vec d}{|\vec F|ยท|\vec d|}=28ยฐ.


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