Answer to Question #284499 in Physics for john

Question

Determine the force of gravity of the meteorites when it reaches one quarter of its distance from the center of Earth if the force of gravity of a meteorite approaching Earth is 50,000 N.

Answer 1

$$F_{new}=\dfrac{Gm_mM_E}{(\dfrac{1}{4}d)^2}=\dfrac{Gm_pM_E}{\dfrac{1}{16}d^2}=16F,$$ $$F_{new}=16\times50000\ N=8\times10^5\ N.$$