Question #283443

A 12N object is attached vertically by a string to a frictionless car that runs along a level track. The car with mass (m) kg covers a distance of 1.25m in 5s after it starts from rest. a)Find the final speed of the car. b)Find the loss in potential energy of 12 N object in falling through distance of 1.25m c) Gain in kinetic energy of the car and the hanging object. d)Mass of the car

1
Expert's answer
2021-12-29T12:34:21-0500

a) Find the final speed of the car.


v=2dt=0.5 m/s.v=\dfrac{2d}t=0.5\text{ m/s}.

b) Find the loss in potential energy of 12 N object in falling through distance of 1.25 m.


ΔE=mgh=121.25=15 J.\Delta E=mgh=12·1.25=15\text{ J}.

c) Gain in kinetic energy of the car and the hanging object.


ΔKE=12mcv2+12Wg2gh=(0.125mc+15) J.\Delta KE=\dfrac12m_cv^2+\dfrac12 \dfrac Wg·2gh=(0.125m_c+15)\text{ J}.


d) Mass of the car:


mc=m2d/t2g2d/t2=12.6 gm_c=m\dfrac{2d/t^2}{g-2d/t^2}=12.6\text{ g}


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