Question #283279

A tube 1.20 m long is closed at one end. A stretched wire

is placed near the open end. The wire is 0.330 m long and has a

mass of 9.60 g. It is fixed at both ends and oscillates in its funda-

mental mode. By resonance, it sets the air column in the tube into

oscillation at that column’s fundamental frequency. Find (a) that

frequency and (b) the tension in the wire.


1
Expert's answer
2021-12-29T12:34:47-0500

Find the frequency (the speed of sound is 343 m/s):


f=c4Lp=34341.2=71.5 Hz.f=\dfrac{c}{4·L_p}=\dfrac{343}{4·1.2}=71.5\text{ Hz}.

Find the tension:


T=4mLwf2=64.8 N.T=4mL_wf^2=64.8\text{ N}.


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