Answer to Question #283132 in Physics for bex

Question #283132

A 4.5 kg dog stands on an 18 kg flatboat at distance D=6.1 m from the shore. It walks 2.4 m along the boat toward shore and then stops. Assuming no friction between the boat and the water, find how far the dog is then from the shore.


1
Expert's answer
2021-12-29T12:35:09-0500

Apply momentum conservation:


0=mbvbmdvd, 0=mbdbtmdddt, 0=mbdbmddd.0=m_bv_b-m_dv_d,\\\space\\ 0=m_b\dfrac{d_b}{t}-m_d\dfrac{d_d}{t},\\\space\\ 0=m_bd_b-m_dd_d.

On the other hand, these displacements added to each other give 2.4 m:


db+dd=2.4 m.d_b+d_d=2.4 \text{ m.}

Solve the system:


dd=1.92 m,dd=0.48 m.d_d=1.92\text{ m},\\ d_d=0.48\text{ m}.

So, dog went 1.92 m forward, and the distance to the shore became 6.1-1.92=4.18 m.


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