Question

A sample of air has a temperature of 40.0◦C and occupies a volume of 2.30ℓ. At what temperature would it occupy a volume of 6.50ℓ?

Answer 1

Given:

$t_i=\rm40.0^\circ C$

$V_i=\rm 2.30\: L$

$V_f=\rm 6.50\: L$

$t_f-?$

The constant pressure process equation says

$$\frac{T_f}{T_i}=\frac{V_f}{V_i}$$

Hence

$$T_f=T_i\frac{V_f}{V_i}=(40.0+273)\frac{6.50}{2.30}=885\:\rm K$$

$$t_f=T_f-273=885-273=612\rm ^\circ C$$