What mass will push on a lever 80cm long. If the moment of 56.96Nm is caused about it's centre shaft?
τ=F⋅d=mg⋅d→m=τ/(g⋅d)=56.96/(9.8⋅0.8)=\tau =F\cdot d=mg\cdot d\to m=\tau/(g\cdot d)=56.96/(9.8\cdot 0.8)=τ=F⋅d=mg⋅d→m=τ/(g⋅d)=56.96/(9.8⋅0.8)=
=7.3 (kg)=7.3\ (kg)=7.3 (kg) . Answer
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