Question

6. Three point charges are fixed at the corners of a right triangle. What is the electric force on the +1.0-pC chargedue to the other two charges?

Answer 1

If all charges are equal and we are to find the force on the charge at the vertex of the right angle, and the right triangle is isosceles with sides of 1 m, the force is:

$$F=\frac{kq^2\sqrt2}{r^2}=9\cdot10^{-15}\text{ N}.$$