Answer to Question #282125 in Physics for Abdikani

Question #282125

A torque of 7.4 N • m is applied to a wheel with a moment of inertia of 0.092 kg . cm?

. What is the resulting

angular acceleration?

Expert's answer

"\\tau=I\\alpha,""\\alpha=\\dfrac{\\tau}{I}=\\dfrac{7.4\\ N\\times m}{0.092\\ kg\\times m^2}=80.4\\ \\dfrac{rad}{s^2}."

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