Question #28209

A sphere of radius R is centered at the origin. A plane intersects this sphere at a distance a from its center such that a<R. determine the volume of the smaller of the regions bound by the sphere and the plane . ( you may use Cartesian coordinates or spherical polar coordinates.)
1

Expert's answer

2013-04-12T08:04:13-0400

QUESTION

A sphere of radius RR is centered at the origin. A plane intersects this sphere at a distance aa from its center such that a<Ra < R . Determine the volume of the smaller of the regions bound by the sphere and the plane. (you may use Cartesian coordinates or spherical polar coordinates.)

SOLUTION:

The region bound by the sphere and the plane called a spherical cap



The volume of the spherical cap is


V=π(Ra)6(3h2+(Ra)2)V = \frac {\pi (R - a)}{6} (3 h ^ {2} + (R - a) ^ {2})


Or


V=π(Ra)23(3R(Ra))=π(Ra)23(2R+a)V = \frac {\pi (R - a) ^ {2}}{3} (3 R - (R - a)) = \frac {\pi (R - a) ^ {2}}{3} (2 R + a)

ANSWER

V=π(Ra)6(3h2+(Ra)2)=π(Ra)23(2R+a)V = \frac {\pi (R - a)}{6} (3 h ^ {2} + (R - a) ^ {2}) = \frac {\pi (R - a) ^ {2}}{3} (2 R + a)

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