Answer to Question #281338 in Physics for haasggdfnsd

Question #281338

A rod 0.5 m long floats vertically in a liquid with 0.3 m above the surface. What is the density of the rod if the relative density of the liquid is 1.2?


1
Expert's answer
2021-12-21T12:16:46-0500

Given:

ρL/ρW=1.2\rho_L/\rho_W=1.2

l=0.5ml=0.5\:\rm m

lsub=0.2ml_{\rm sub}=0.2\:\rm m




The equilibrium condition gives

Fbuoyant=mgF_{\rm buoyant}=mg

gρLlsubA=gρlAg\rho_Ll_{\rm sub}A=g\rho lA

ρ=ρLlsub/l=1200kg/m30.2/0.5=480kg/m3\rho=\rho_L l_{\rm sub}/l=\rm1200\: kg/m^3*0.2/0.5=480\:kg/m^3


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