A standing wave on a string has a frequency of 100 Hz, a wavelength of 0.04 m, and an amplitude of 2 mm. The transverse velocity of the point x = 0.02 m, is:
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Expert's answer
2021-12-20T10:31:06-0500
The transverse velocity is
"v(x,t)=-A\u03c9 \\cos (k x - \u03c9 t + \u03c6),\\\\\nv(x,t)=-A(2\\pi f) \\cos [(2\\pi\/\\lambda) x - (2\\pi f) t+0],\\\\\nv(0.02,t)=1.26\\cos(3.14-628t)."
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