Answer to Question #281318 in Physics for ahmad

Question #281318

A standing wave on a string has a frequency of 100 Hz, a wavelength of 0.04 m, and an amplitude of 2 mm. The transverse velocity of the point x = 0.02 m, is:


1
Expert's answer
2021-12-20T10:31:06-0500

The transverse velocity is


v(x,t)=Aωcos(kxωt+φ),v(x,t)=A(2πf)cos[(2π/λ)x(2πf)t+0],v(0.02,t)=1.26cos(3.14628t).v(x,t)=-Aω \cos (k x - ω t + φ),\\ v(x,t)=-A(2\pi f) \cos [(2\pi/\lambda) x - (2\pi f) t+0],\\ v(0.02,t)=1.26\cos(3.14-628t).


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment