Question #281271

An automobile moves with a constant speed of 120 km/hr around a track of 50 m diameter.


What is the angular velocity and the period of motion? (

1
Expert's answer
2021-12-23T10:50:08-0500

120 km/h=33.33 m/s120\ km/h=33.33\ m/s


v=ωrω=v/r=33.33/25=1.33 (rad/s)v=\omega\cdot r\to \omega = v/r=33.33/25=1.33\ (rad/s)


T=2πr/v=23.1425/33.33=4.7 (s)T=2\pi r/v=2\cdot3.14\cdot25/33.33=4.7\ (s)


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