An automobile moves with a constant speed of 120 km/hr around a track of 50 m diameter.
What is the angular velocity and the period of motion? (
120 km/h=33.33 m/s120\ km/h=33.33\ m/s120 km/h=33.33 m/s
v=ω⋅r→ω=v/r=33.33/25=1.33 (rad/s)v=\omega\cdot r\to \omega = v/r=33.33/25=1.33\ (rad/s)v=ω⋅r→ω=v/r=33.33/25=1.33 (rad/s)
T=2πr/v=2⋅3.14⋅25/33.33=4.7 (s)T=2\pi r/v=2\cdot3.14\cdot25/33.33=4.7\ (s)T=2πr/v=2⋅3.14⋅25/33.33=4.7 (s)
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