A car moved horizontally on a road at a constant velocity. If the mass of the car is 1,000 kg and the friction between the tires and the road was 1,500 N, what was the coefficient of friction?
F−Ffr=0→F=FfrF-F_{fr}=0\to F=F_{fr}F−Ffr=0→F=Ffr
Ffr=μN=μmg→μ=Ffr/(mg)=1500/(1000⋅9.8)=F_{fr}=\mu N=\mu mg\to \mu=F_{fr}/(mg)=1500/(1000\cdot9.8)=Ffr=μN=μmg→μ=Ffr/(mg)=1500/(1000⋅9.8)=
=0.153=0.153=0.153 . Answer
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