Answer to Question #281226 in Physics for Venus

Question

A pitcher throws a 0.2kg baseball. IF the ball starts from rest and leaves the pitcher's hand a velocity of 30m/s, how much work is done on the ball? Show complete solution.

Answer 1

Given:

$m=0.2\:\rm kg$

$v_i=0\:\rm m/s$

$v_f=30\:\rm m/s$

The work done is equal to change in kinetic energy

$$W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\rm\frac{30^2*0.2}{2}-\frac{0^2*0.2}{2}=90\: J$$