Question #281223

A 0.075kg arrow is fire horizontally. The bowstring exerts an average force of 65N on the arrow over a distance of 0.09m. With what speed did the arrow leave on bow. Show complete solution.


1
Expert's answer
2021-12-20T10:31:40-0500

Find the acceleration:


a=F/m.a=F/m.

The speed:


v=2ad=2Fmd=2650.0750.09=12.5 m/s.v=\sqrt{2ad}=\sqrt{2\frac Fmd}=\sqrt{2·\frac{65}{0.075}·0.09}=12.5\text{ m/s}.


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