Question

Solve for the specific gravity

1. Coconut oil has density of 930kg/ m³

2. Sea water has a density of 1025 kg/m³

Answer 1

By the definition of SG, we have:

1)

$$SG=\dfrac{\rho_{oil}}{\rho_{w}}=\dfrac{930\ \dfrac{kg}{m^3}}{1000\ \dfrac{kg}{m3}}=0.93$$

2)

$$SG=\dfrac{\rho_{sea\ water}}{\rho_{w}}=\dfrac{1025\ \dfrac{kg}{m^3}}{1000\ \dfrac{kg}{m3}}=1.025$$