Solve for the specific gravity
1. Coconut oil has density of 930kg/ m³
2. Sea water has a density of 1025 kg/m³
By the definition of SG, we have:
1)
"SG=\\dfrac{\\rho_{oil}}{\\rho_{w}}=\\dfrac{930\\ \\dfrac{kg}{m^3}}{1000\\ \\dfrac{kg}{m3}}=0.93"
2)
"SG=\\dfrac{\\rho_{sea\\ water}}{\\rho_{w}}=\\dfrac{1025\\ \\dfrac{kg}{m^3}}{1000\\ \\dfrac{kg}{m3}}=1.025"
Comments
Leave a comment