A railway track that is 50 m long, with initial temperature of 10 °C is subjected to a great heat. How much will it expand when its temperature is tripled [α= 13 ´ 10-6 / °C]?
ΔL=αLΔT=13⋅10−6⋅50⋅20=0.013 (m)=1.3 (cm)\Delta L=\alpha L \Delta T=13\cdot10^{-6}\cdot50\cdot20=0.013\ (m)=1.3\ (cm)ΔL=αLΔT=13⋅10−6⋅50⋅20=0.013 (m)=1.3 (cm) . Answer
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