A 12kg mass is placed on a 30° frictionless inclined plane attached to a pulley connected to a hanging mass of 5kg. What is the acceleration of the system?
12⋅gsin30°−T=12⋅a12\cdot g\sin30°-T=12\cdot a12⋅gsin30°−T=12⋅a
5⋅g−T=−5⋅a→T=5⋅g+5⋅a5\cdot g-T=-5\cdot a \to T=5\cdot g+5\cdot a5⋅g−T=−5⋅a→T=5⋅g+5⋅a
12⋅gsin30°−5⋅g−5⋅a=12⋅a12\cdot g\sin30°-5\cdot g-5\cdot a=12\cdot a12⋅gsin30°−5⋅g−5⋅a=12⋅a
a=(12⋅9.8⋅sin30°−5⋅9.8)/17=0.58 (m/s2)a=(12\cdot9.8\cdot\sin30°-5\cdot9.8)/17=0.58\ (m/s^2)a=(12⋅9.8⋅sin30°−5⋅9.8)/17=0.58 (m/s2)
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