7. What is the mass of a cubic meter of air at 20oC at sea level?
pV=mMRT→101325⋅1=m0.02896⋅8.31⋅293→pV=\frac{m}{M}RT\to101325\cdot1=\frac{m}{0.02896}\cdot8.31\cdot293\topV=MmRT→101325⋅1=0.02896m⋅8.31⋅293→
m=1.21 kgm=1.21 \ kgm=1.21 kg . Answer
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