Answer to Question #280220 in Physics for tanya

Question

A 0.65 kg body when attached to a spring of force constant 225N/m oscillates with a maximum speed of 0.15 m/s. Find its amplitude and acceleration of the mass when it passes its equilibrium position.

Answer 1

The maximum velocity of the mass when it passes its equilibrium position

$kx^2/2=mv^2/2\to v=x\sqrt{\frac{k}{m}}=0.15\cdot\sqrt{\frac{225}{0.65}}=2.8\ (m/s)$

The acceleration of the mass when it passes its equilibrium position

$a=0$