1.A 50 N force is applied to a 20 kg cart which was displaced at 150 m from rest on a surface applying an opposing force of 30N.
2.Explain your reasoning in each item briefly and concisely.
1.
2. W=F⋅s⋅cosα=(50−30)⋅150⋅1=3000 (J)W=F\cdot s\cdot\cos\alpha=(50-30)\cdot150\cdot1=3000\ (J)W=F⋅s⋅cosα=(50−30)⋅150⋅1=3000 (J)
3. ΔKE=W=3000 (J)\Delta KE=W=3000\ (J)ΔKE=W=3000 (J)
4. KE=mv22→v=2⋅KE/m=2⋅3000/20=17.32 (m/s)KE=\frac{mv^2}{2}\to v=\sqrt{2\cdot KE/m}=\sqrt{2\cdot 3000/20}=17.32\ (m/s)KE=2mv2→v=2⋅KE/m=2⋅3000/20=17.32 (m/s)
The potential energy of a body
PE=mghPE=mghPE=mgh .
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments