Answer to Question #279607 in Physics for xieess

Question

2. What is the image distance and image size if a 3.00-cm tall light bulb is placed at a distance of 30.5 cm from a diverging lens having a focal length of -10.2 cm?

Answer 1

$-\frac{1}{F}=\frac{1}{a}+\frac{1}{b}\to-\frac{1}{0.102}=\frac{1}{0.305}+\frac{1}{b}\to b=-0.0764\ (m)$

$H/h=-b/a\to H=-bh/a=-(-0.0764\cdot0.03)/0.305=0.0075\ (m)$